xref: /dragonfly/games/ching/printching/printching.c (revision d808242906dd621413f6e34f9812f1dd1463041a)
1 /*        $NetBSD: printching.c,v 1.5 2011/08/31 16:24:55 plunky Exp $          */
2 
3 /*
4  * Copyright (c) 1988, 1993
5  *        The Regents of the University of California.  All rights reserved.
6  *
7  * This code is derived from software contributed to Berkeley by
8  * Guy Harris.
9  *
10  * Redistribution and use in source and binary forms, with or without
11  * modification, are permitted provided that the following conditions
12  * are met:
13  * 1. Redistributions of source code must retain the above copyright
14  *    notice, this list of conditions and the following disclaimer.
15  * 2. Redistributions in binary form must reproduce the above copyright
16  *    notice, this list of conditions and the following disclaimer in the
17  *    documentation and/or other materials provided with the distribution.
18  * 3. All advertising materials mentioning features or use of this software
19  *    must display the following acknowledgement:
20  *        This product includes software developed by the University of
21  *        California, Berkeley and its contributors.
22  * 4. Neither the name of the University nor the names of its contributors
23  *    may be used to endorse or promote products derived from this software
24  *    without specific prior written permission.
25  *
26  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
27  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
28  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
29  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
30  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
31  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
32  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
33  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
34  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
35  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
36  * SUCH DAMAGE.
37  *
38  * @(#)ching.phx.c  8.1 (Berkeley) 5/31/93
39  */
40 
41 /*
42  * printching - Print NROFF/TROFF source of change, given the line values.
43  */
44 #include <stdio.h>
45 #include <stdlib.h>
46 #include <string.h>
47 #include "ching.h"
48 #include "pathnames.h"
49 
50 static int changes(void);
51 static int codem(int a);
52 static int doahex(void);
53 static void phx(int hexagram, int flag);
54 
55 static const struct {
56           int       lines;              /* encoded value of lines */
57           int       trinum;             /* trigram number */
58 } table[] = {
59           { 777, 0 },                   /* 1 */
60           { 887, 1 },                   /* 4 */
61           { 878, 2 },                   /* 6 */
62           { 788, 3 },                   /* 7 */
63           { 888, 4 },                   /* 8 */
64           { 778, 5 },                   /* 5 */
65           { 787, 6 },                   /* 3 */
66           { 877, 7 },                   /* 2 */
67 };
68 
69 /*
70  * Gives hexagram number from two component trigrams.
71  */
72 static const int crosstab[8][8] = {
73           {1,  34, 5,  26, 11, 9,  14, 43},
74           {25, 51, 3,  27, 24, 42, 21, 17},
75           {6,  40, 29, 4,  7,  59, 64, 47},
76           {33, 62, 39, 52, 15, 53, 56, 31},
77           {12, 16, 8,  23, 2,  20, 35, 45},
78           {44, 32, 48, 18, 46, 57, 50, 28},
79           {13, 55, 63, 22, 36, 37, 30, 49},
80           {10, 54, 60, 41, 19, 61, 38, 58}
81 };
82 
83 static int trigrams[6];
84 static int moving[6];
85 
86 static FILE *chingf;                    /* stream to read the hexagram file */
87 
88 int
main(int argc,char ** argv)89 main(int argc, char **argv)
90 {
91           char *hexptr;                 /* pointer to string of lines */
92           char hexstr[6+1];   /* buffer for reading lines in */
93           int i;
94 
95           if (argc < 2)
96                     hexptr = fgets(hexstr, 6+1, stdin);
97           else
98                     hexptr = argv[1];
99           if (hexptr == NULL || strlen(hexptr) != 6) {
100                     fprintf(stderr, "What kind of a change is THAT?!?\n");
101                     exit(1);
102           }
103           for (i = 0; i < 6; i++) {
104                     trigrams[i] = hexptr[i] - '0';
105                     if (trigrams[i] == 6 || trigrams[i] == 9)
106                               moving[i] = 1;
107                     else
108                               moving[i] = 0;
109           }
110           if ((chingf = fopen(_PATH_HEX, "r")) == NULL) {
111                     fprintf(stderr, "ching: can't read %s\n", _PATH_HEX);
112                     exit(2);
113           }
114           phx(doahex(), 0);
115           if (changes())
116                     phx(doahex(), 1);
117           exit(0);
118 }
119 
120 /*
121  * Compute the hexagram number, given the trigrams.
122  */
123 static int
doahex(void)124 doahex(void)
125 {
126           int lower, upper;   /* encoded values of lower and upper trigrams */
127           int lnum = 0, unum = 0;       /* indices of upper and lower trigrams */
128           int i;
129 
130           lower = codem(0);
131           upper = codem(3);
132           for (i = 0; i < 8; i++) {
133                     if (table[i].lines == lower)
134                                lnum = table[i].trinum;
135                     if (table[i].lines == upper)
136                                unum = table[i].trinum;
137           }
138           return(crosstab[lnum][unum]);
139 }
140 
141 /*
142  * Encode a trigram as a 3-digit number; the digits, from left to right,
143  * represent the lines.  7 is a solid (yang) line, 8 is a broken (yin) line.
144  */
145 static int
codem(int a)146 codem(int a)
147 {
148           int code, i;
149           int factor[3];
150 
151           factor[0] = 1;
152           factor[1] = 10;
153           factor[2] = 100;
154           code = 0;
155 
156           for (i = a; i < a + 3; i++) {
157                     switch(trigrams[i]) {
158 
159                     case YYANG:
160                     case OYANG:
161                               code += factor[i%3]*7;
162                               break;
163 
164                     case OYIN:
165                     case YYIN:
166                               code += factor[i%3]*8;
167                               break;
168                     }
169           }
170           return(code);
171 }
172 
173 /*
174  * Compute the changes based on moving lines; return 1 if any lines moved,
175  * 0 if no lines moved.
176  */
177 static int
changes(void)178 changes(void)
179 {
180           int cflag;
181           int i;
182 
183           cflag = 0;
184           for (i = 0; i < 6; i++) {
185                     if (trigrams[i] == OYIN) {
186                               trigrams[i] = YYANG;
187                               cflag++;
188                     } else if (trigrams[i] == OYANG) {
189                               trigrams[i] = YYIN;
190                               cflag++;
191                     }
192           }
193           return(cflag);
194 }
195 
196 /*
197  * Print the NROFF/TROFF source of a hexagram, given the hexagram number;
198  * if flag is 0, print the entire source; if flag is 1, ignore the meanings
199  * of the lines.
200  */
201 static void
phx(int hexagram,int flag)202 phx(int hexagram, int flag)
203 {
204           char textln[128+1];           /* buffer for text line */
205           char *lp;                     /* pointer into buffer */
206           int thishex;                            /* number of hexagram just read */
207           int lineno;                             /* number of line read in */
208           int allmoving;                          /* 1 if all lines are moving */
209           int i;
210 
211           /*
212            * Search for the hexagram; it begins with a line of the form
213            * .H <hexagram number> <other data>.
214            */
215           rewind(chingf);
216           for (;;) {
217                     if (fgets(textln, sizeof(textln), chingf) == NULL) {
218                               fprintf(stderr, "ching: Hexagram %d missing\n",
219                                   hexagram);
220                               exit(3);
221                     }
222                     lp = &textln[0];
223                     if (*lp++ != '.' || *lp++ != 'H')
224                               continue;
225                     while (*lp++ == ' ')
226                               ;
227                     lp--;
228                     thishex = atoi(lp);
229                     if (thishex < 1 || thishex > 64)
230                               continue;
231                     if (thishex == hexagram)
232                               break;
233           }
234 
235           /*
236            * Print up to the line commentary, which ends with a line of the form
237            * .L <position> <value>
238            */
239           fputs(textln, stdout);
240           for (;;) {
241                     if (fgets(textln, sizeof(textln), chingf) == NULL) {
242                               fprintf(stderr, "ching: Hexagram %d malformed\n",
243                                   hexagram);
244                               exit(3);
245                     }
246                     lp = &textln[0];
247                     if (*lp++ == '.') {
248                               if (*lp++ == 'L')
249                                         break;
250                     }
251                     fputs(textln, stdout);
252           }
253 
254           /*
255            * Now print the line commentaries, if this is the first hexagram.
256            */
257           if (flag)
258                     return;
259 
260           /*
261            * If a line is moving, print its commentary.
262            * The text of the commentary ends with a line either of the form
263            * .L <position> <value>
264            * or of the form
265            * .LA <value>
266            * or of the form
267            * .H <hexagram number> <other arguments>
268            */
269           allmoving = 1;
270           for (i = 0; i < 6; i++) {
271                     while (*lp++ == ' ')
272                               ;
273                     lp--;
274                     lineno = atoi(lp);
275                     if (i + 1 != lineno) {
276                               fprintf(stderr, "ching: Hexagram %d malformed\n",
277                                   hexagram);
278                               exit(3);
279                     }
280                     if (moving[i])
281                               fputs(textln, stdout);
282                     else
283                               allmoving = 0;
284                     for (;;) {
285                               if (fgets(textln, sizeof(textln), chingf) == NULL)
286                                         break;
287                               lp = &textln[0];
288                               if (*lp++ == '.' && (*lp == 'L' || *lp == 'H')) {
289                                         lp++;
290                                         break;
291                               }
292                               if (moving[i])
293                                         fputs(textln, stdout);
294                     }
295           }
296 
297           /*
298            * If all the lines are moving, print the commentary for that; it
299            * ends with a line of the form
300            * .H <hexagram number> <other arguments>
301            */
302           if (*lp == 'A' && allmoving) {
303                     fputs(textln, stdout);
304                     for (;;) {
305                               if (fgets(textln, sizeof(textln), chingf) == NULL)
306                                         break;
307                               lp = &textln[0];
308                               if (*lp++ == '.' || *lp++ == 'H')
309                                         break;
310                               fputs(textln, stdout);
311                     }
312           }
313 }
314